8y^2-11y+3=0

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Solution for 8y^2-11y+3=0 equation: 



8y^2-11y+3=0

a = 8; b = -11; c = +3;
Δ = b2-4ac
Δ = -112-4·8·3
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-5}{2*8}=\frac{6}{16}
=3/8
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+5}{2*8}=\frac{16}{16}
=1
$

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